-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy pathdiameterofBinaryTree*
More file actions
32 lines (29 loc) · 904 Bytes
/
Copy pathdiameterofBinaryTree*
File metadata and controls
32 lines (29 loc) · 904 Bytes
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
/*************************/
Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
Example:
Given a binary tree
1
/ \
2 3
/ \
4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges between them.
/*************************/
class Solution {
public:
int diameterOfBinaryTree(TreeNode * root) {
int res = 0;
maxDepth(root, res);
return res;
}
int maxDepth(TreeNode *node, int &res) {
if (node == NULL) {
return 0;
}
int left = maxDepth(node->left, res);
int right = maxDepth(node->right, res);
res = max(res, left + right);
return max(left, right) + 1;
}
};