-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy pathmain.cpp
More file actions
93 lines (82 loc) · 2 KB
/
main.cpp
File metadata and controls
93 lines (82 loc) · 2 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
// Source: https://leetcode.com/problems/spiral-matrix
// Title: Spiral Matrix
// Difficulty: Medium
// Author: Mu Yang <http://muyang.pro>
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// Given an `m x n` `matrix`, return all elements of the `matrix` in spiral order.
//
// **Example 1:**
// https://assets.leetcode.com/uploads/2020/11/13/spiral1.jpg
//
// ```
// Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
// Output: [1,2,3,6,9,8,7,4,5]
// ```
//
// **Example 2:**
// https://assets.leetcode.com/uploads/2020/11/13/spiral.jpg
//
// ```
// Input: matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12]]
// Output: [1,2,3,4,8,12,11,10,9,5,6,7]
// ```
//
// **Constraints:**
//
// - `m == matrix.length`
// - `n == matrix[i].length`
// - `1 <= m, n <= 10`
// - `-100 <= matrix[i][j] <= 100`
//
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
#include <vector>
using namespace std;
class Solution {
public:
vector<int> spiralOrder(vector<vector<int>>& matrix) {
int m = matrix.size();
int n = matrix[0].size();
vector<int> ans;
ans.reserve(m * n);
// boundaries
auto left = 0;
auto right = n - 1;
auto up = 0;
auto down = m - 1;
while (true) {
// Right
if (left > right) {
break;
}
for (auto i = left; i <= right; i++) {
ans.push_back(matrix[up][i]);
}
up++;
// Down
if (up > down) {
break;
}
for (auto j = up; j <= down; j++) {
ans.push_back(matrix[j][right]);
}
right--;
// Left
if (left > right) {
break;
}
for (auto i = right; i >= left; i--) {
ans.push_back(matrix[down][i]);
}
down--;
// Down
if (up > down) {
break;
}
for (auto j = down; j >= up; j--) {
ans.push_back(matrix[j][left]);
}
left++;
}
return ans;
}
};