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PathSum.cpp
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50 lines (42 loc) · 1.04 KB
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/*
Question:
Path Sum
Asked in:
Microsoft
Yahoo
Amazon
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
Example :
Given the below binary tree and sum = 22,
5
/ \
4 8
/ / \
11 13 4
/ \ \
7 2 1
return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
Return 0 / 1 ( 0 for false, 1 for true ) for this problem
*/
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
int Solution::hasPathSum(TreeNode* A, int B) {
if(A==NULL)
{
return B==0;
}
if(A->left and A->right)
return hasPathSum(A->left,B-A->val)||hasPathSum(A->right,B-A->val);
if(A->left)
return hasPathSum(A->left,B-A->val);
if(A->right)
return hasPathSum(A->right,B-A->val);
return A->val==B;
}