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11.Container_With_Most_Water.cpp
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33 lines (28 loc) · 1.38 KB
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// Solution for Container With Most Water contributed by nikki9119.
/*
Problem URL: https://leetcode.com/problems/container-with-most-water/
Given n non-negative integers a1, a2, ..., an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of the line i is at (i, ai) and (i, 0).
Find two lines, which, together with the x-axis forms a container, such that the container contains the most water.
Notice that you may not slant the container.
Example:
Input: height = [1,8,6,2,5,4,8,3,7]
Output: 49
Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.
*/
#include<bits/stdc++.h>
using namespace std;
class Solution {
public:
int maxArea(vector<int>& height) {
int maxArea=0, left=0, right=height.size()-1; //initialize two pointers, left and right
while(left < right){
maxArea = max(maxArea,min(height[left],height[right])*(right-left)); //store the maximum area, the shorter wall is selected as the height.
if(height[left] < height[right]) //if left wall is shorter than the right wall move left pointer to the right, else move right pointer to the left
left++;
else
right--;
}
return maxArea;
}
};
// Time Complexity: O(n)