working solution

[avcode3]

No description provided.

[super30admin]

Strengths:

• The solution correctly implements Pascal's Triangle generation.
• The code is structured with clear variable names and logical steps.
• The base cases are handled explicitly, which makes the code easy to understand.

Areas for Improvement:

• The solution can be made more general by not hardcoding the first two rows. Instead, you can start with the first row and then generate each subsequent row in a loop without checking for numRows=2. This would simplify the code and make it more maintainable.
• The outer loop variable i is not used inside the loop. Consider using a more descriptive name or using an underscore to indicate it is unused.
• You can avoid the explicit base cases by initializing the triangle with the first row and then looping from row index 1 to numRows-1. This approach is taken in the reference solution and reduces redundancy.
• Consider adding comments to explain the logic, especially for someone who might be new to Pascal's Triangle.

Revised Approach Suggestion:
You can refactor the code as follows:

class Solution:
    def generate(self, numRows: int) -> List[List[int]]:
        triangle = []
        for row_num in range(numRows):
            row = [1] * (row_num + 1)
            for j in range(1, row_num):
                row[j] = triangle[row_num-1][j-1] + triangle[row_num-1][j]
            triangle.append(row)
        return triangle

This approach initializes each row with ones and then updates the inner values by referencing the previous row. It handles all cases without explicit checks for numRows=1 or 2.